Question

celculate the no. of oxygen atom in 10 g caco3

Answer 1

# 1 0 g = 0.1 mol = 6.02 x 10^22 CaCO3 units

6.02 x 10^22 x 5 = 3.01 x 10^23 = 30.1 x 10

Answer 2

Hope this helps.......