Math, asked by SrijeetaRay2433, 2 months ago

Celine had 35kg of pistachios. She sold 3/5 of the pistachios on Saturday and 4/7 of the remaining pistachios on sunday. She then packed the remaining pistacachitos into bags, wach containing 5/8 kg of pistachios. How many bags of pistachios did Celine pack at most? What was the masss

Answers

Answered by tanyatiwari1329
3

Answer:

3/5of 35= 21 kg

4/of remaining=4/7 of 21= 12kg

Answered by iialicealtacc
0

Answer:

A) 3 3/4

B) 2 1/4

Step-by-step explanation:

We already know the number, it is 35kg there is no need to divide

35 x 3/5 = 35x3/5 = 105/5 (simplified = 21)

35 - 21 = 14 (remaining pistachios on Sunday)

14 x 4/7 = 14 x 4 /7  = 56/7 (simplified = 8 also sold on Sunday)

14 - 8 = 6 remaining from the one sold on Sunday.

A solution) 6/1 x 5/6 = 30/6 = 15/4 = (simplified = 3 3/4)

B solution) 3 3/4 = 6 - 15/14 = 6/1 = 24/4 - 15/4 = 24 - 15/4 = 9/4 (simplified =

2 1/4)

Forgot how to solve it but just copied from my very old notes

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