cell of EMF 2 volt with internal resistance 2 ohm and the external resistance at home from a closed circuit find the potential difference between the two ends of the external resistance
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# Correct question -
Q. Cell of EMF 2 volt with internal resistance 2 ohm and the external resistance 8 ohm form a closed circuit. Find the potential difference between the two ends of the external resistance.
◆ Answer -
V = 1.6 V
◆ Explaination -
Current flowing through circuit is -
I = E / (R + r)
I = 2 / (8 + 2)
I = 0.2 A
Voltage across external resistance is -
V = I.R
V = 0.2 × 8
V = 1.6 V
Hence, voltage across external resistance will be 1.6 V.
Thanks dear...
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