Question

cell of emf E volt, internal resistance r is being charged is being charged with current of i ampere, then the terminal potential difference is:

0/1

E+ir

E

ir

E-ir

​

Answer 1

Explanation:

her is your answers l hope it help you

Answer 2

Answer:

The terminal potential difference is $E-Ir$.

Explanation:

An cell of EMF is defined as the force of the cell which is electromotive and the cell is said to be having the potential difference which is maximum and has a difference between two electrodes of a cell.

• The EMF of the cell consists of:

Helps in determining the electrochemical cell that is galvanic.

• Types of the electrochemical cell:

1) Galvanic

2) Daniell

Formula of the EMF of cell:

ε=$E/Q$

Here,

ε is electromagnetic force

E is circuit in energy

Q is circuit of the charge

• The terminal potential difference is defined as the potential in which the difference will come across the cells of the terminals.
• When there will be no internal resistance present, the potential difference in the terminal will be equal to the value of the emf.

Given that:

Cell of emf E volt, internal resistance r is being charged is being charged with current of i ampere,

To find:

terminal potential difference is =?

Solution:

Let us assume that, by applying a formula,

Let

$V = Ir$

Then,

E = terminal voltage+ internal voltage

Here,

V is known as terminal voltage

v is known as internal voltage

$E –v = V$

$E-Ir$

This is called as the terminal potential difference.

#SPJ3