Question

cell supply a current of 0.9 A through a 2 ohm reaistor and current of 0.3 A through a 7 ohm resistor.what is the resistor of the cell?​

Answer 1

Answer:

Explanation:

We know I=E/(R+r)

Where r=internal resistance

Now

0.9(2+r)=E

and 0.3(7+r)=E

So 0.9(2+r)=0.3(7+r)

1.8+0.9r=2.1+0.3r

0.6r=0.3

r=1/2

r=0.5 ohms

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