Cells present in a cube-shaped ideal crystal of
NaCl of mass 1.00 g are [Atomic masses : Na =23, Cl = 35.5]
(a) 5.14 × 10²¹ unit cells
(b) 1.28 × 10²¹ unit cells
(c) 1.71 × 10²¹ unit cells
(d) 2.57 × 10²¹ unit cells
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Answer:
So, each unit cell has 4 atoms of each Na+ and Cl-. Hence there are total 4 molecules of NaCl in each unit cell. As the mass of -Avogadro number of molecules- of NaCl is 58.5g. So, 2.575×10^21 unit cells contains 1gm of NaCl molecules.
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How many unit cells are present in a cube shaped ideal crystal
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