Question

cent is
2. A dealer comes from Mathura to Delhi to buy an article which costs
12% less in Delhi than in Mathura.
His expenses are * 240 and he makes a profit of 3 300 on selling the article in Mathura. What did the
called
article cost in Mathura? What is his profit percent?
goods to an agent at a profit of 20%. The agent's wholesale price to the shopkeeper
goods at a profit of 25%. Find the manufacturing price​

Answer 1

Step-by-step explanation:

The article cost in Mathura is Rs. 272.73 and the dealer's profit percentage is 138.64%.

Step-by-step explanation:

Let the article cost in Mathura is Rs. x.

So, the cost of the article in Delhi is 12% less i.e. x(1 - \frac{12}{100}) = 0.88xx(1−

100

12

)=0.88x .

Now, given that 0.88x = 240

⇒ x = 272.73 Rs. (Answer)

Now, the dealer sells the article in Mathura at 300 Rs. profit.

So, the selling price in Mathura is (272.73 + 300) = 572.73 Rs.

Hence, the profit percentage of the dealer is \frac{572.73 - 240}{240}\times 100 \% = 138.64\%

240

572.73−240

×100%=138.64% . (Answer).