Question

Center of the circle x2+y2-4x-6y+3=0

Answer 1

Answer:

in an x–y Cartesian coordinate system,  

the circle with centre coordinates (a, b)  

and radius r  

is the set of all points (x, y)  

such that  

( x - a ) ² + ( y - b ) ² = r ²  

Let's now convert the given equation to this form;  

x ² + y ² - 4x - 6y + 3 = 0  

x ² - 4x + y ² - 6y = -3  

x ² - 4x + 4 + y ² - 6y + 9 = -3 + 4 + 9  

( x ² - 4x + 4 ) + ( y ² - 6y + 9 ) = 10  

( x - 2 ) ² + ( y - 3 ) ² = ( √10 ) ²  

coordinates of center is ( 2, 3 )  

radius of circle is √10 = 2.236  

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Answer 2

Answer:

see the attachment for answer

Step-by-step explanation:

so your final answer is-

Center is (2,3).

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