Question

Centre
drawn
two concentric circles of radil 15cM, 12cm are drawn
find the length of chord of larger circle which
touches the smaller circle​

Answer 1

Answer:

AP=9cm

Step-by-step explanation:

r1=15cm and R2=12cm

draw a chord AB tangent to C2 at point p

Join O-A and O-B

Op=12cm..(Radius of smaller circle )

OA=OB=15cm(radius of bigger circle )

AB is tangent to C2 and Op is perpendicular AB

angle OPA = angle OPB=90 degree

by using Pythagoras theOrem

OA²=OP²+AP²

AP²=OA²-OP²

AP²=15²-12²

AP²=225-144

AP²=81

AP=√81

AP=9cm

similarly PB =9cm

AB=AP+PB=9+9=18cm

hence ,18cm