Question

Centre is (30) and radius is 5 units


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Answer 1

Answer:

$equation \: of \: given \: circle \: \: \: \: \\ {x}^{2} + {y }^{2} - 6x = 16$

Step-by-step explanation:

${(x - 3)}^{2} + {(y - 0)}^{2} = {5}^{2} \\ \\ {x}^{2} + {y}^{2} - 6x + 9 - 25 = 0 \\ \\ {x}^{2} + {y }^{2} - 6x = 16$

Answer 2

Answer:

equationofgivencircle

x

2

+y

2

−6x=16

Step-by-step explanation:

\begin{gathered} {(x - 3)}^{2} + {(y - 0)}^{2} = {5}^{2} \\ \\ {x}^{2} + {y}^{2} - 6x + 9 - 25 = 0 \\ \\ {x}^{2} + {y }^{2} - 6x = 16\end{gathered}

(x−3)

2

+(y−0)

2

=5

2

x

2

+y

2

−6x+9−25=0

x

2

+y

2

−6x=16