Question

centre of a circle is 6,2 and radius is 10cm this circle cut the y axis at a and b draw a rough figure find the coordinates of a and b

Answer 1

Given-

AB is a tangent to a circle with centre as P and radius PT=6cm.

AB touches the circle at T.

PB intersects the circumference at Q and AB at B such that ∠TPB=60

o

.

To find out- PB

Solution-

PT=PQ=6cm ...(given)

TQ is joined.

Then, ΔPQT is isosceles.

∴∠PTQ=∠PQT

i.e ∠PTQ+∠PQT=2(∠PTQor∠PQT)

So, by the angle sum property of triangles, we have

∠TPQ+2∠PTQ=180

o

⟹60

o

+2∠PTQ=180

o

⟹∠PTQ=60

o

=∠PQT

So, ΔPQT is equilater