Question

Centre of a circle is at (5,3) and its radius is 5. Find length of chord bisected at (3,2)

Answer 1

Answer:

The are just asking to double the distance between (5,3) and (3,2)

$= 2 \times \sqrt{(3 - 2)^{2} + (5 - 3)^{2} } \\ = 2 \times \sqrt{5} \\ = \sqrt{20} \: units$