Question

centre of circle is p,chord BQ=5cm BQ=RS andPM | BQ, PN | RS, PM=2.8cm​

Answer 1

Step-by-step explanation:

Radius= 5cm

base=2.8 cm

by Pythagoras theory

${h}^{2} = {p}^{2} + {b}^{2} \\ {h}^{2} = {5}^{2} + {2.8}^{2} \\ h = \sqrt{ {5}^{2} + {2.8}^{2} } \\ h = 12.84 \: cm$

Answer 2

radius = 5 cm

base = 2.8 cm

by phythgoras theorm

h2^ = p2^+b2^

      =  under root 5cm2^+2.8cm2^

       = 12.84 cm