Question

Centre of circle Q is on y-axis and the circle passes trough the points (0,7) and (0,-7). Circle intersects the positive x-axis at (P,0) what is the value of 'p'

Answer 1

Answer:

P=7

Step-by-step explanation:

We know the circle passes through (7,0) and (-7,0)

So it's radius is 7units

The circle intersects at the x-axis at P, 0 inorder to satisfy the Lenght if radius it should pass through (-P, 0) at the negative x-axis

So by applying distance formula we get

$\sqrt({p + p } )^{2} = 14$

$\sqrt({2p)}^{2} = 14$

2p=14

P=7

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