Question

Centre of gravity of a trapezium with parallel sides a and b lies at a distance y from the base b is

Answer 1

Answer:

The center of gravity of a trapezium with parallel sides 'a' and 'b' lies at a distance of 'y' from the base 'b', as shown in the below figure. The value of 'y' is

Engineering Mechanics mcq question image

A. h [(2a + b)/(a + b)]

B. (h/2) [(2a + b)/(a + b)]

C. (h/3) [(2a + b)/(a + b)]

D. (h/3) [(a + b)/(2a + b)]

Answer: Option C

Answer 2

Answer:

Centre of gravity of a trapezium with parallel sides a and b lies at a distance y from the base b is $Y = h (b+2a) / 3 (b + a)$

Explanation:

The center of gravity of a trapezoid can be estimated by dividing the trapezoid in two triangles.

The center of gravity is the intersection between the middle orange line and the line between the triangles centers of gravity.

For any trapezoid with parallel sides a and b

(Where b is the base) and height h,

The centroid is given by the following formula:

$Y = h (b+2a) / 3 (b + a)$