Centre of the circle P is on the line x+y+7=0.line 3x+4y=4 is a tangent line for the circle at point Q (-4,-4) find equation of the line
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Step-by-step explanation:
3x−4y+4=0 and 3x−4y−
2
7
=0 are two parallel tangents of the same circle.
Then perpendicular distance between these parallel lines is equal to diameter of that circle.
∴2r=
∣
∣
∣
∣
∣
∣
∣
∣
3
2
+4
2
4+
2
7
∣
∣
∣
∣
∣
∣
∣
∣
=
2×5
15
r=
20
15
=
4
3
⇒ radius of the circle =
4
3
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