Centrifugal force derivation
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The force of a moving body is given as
F = ma........(1)
From the figure, we can write the expression
= PQ→PQ→ + QS→QS→ = PS→PS→
= -v1v1 + v2v2
= ΔvΔv
= ΔvΔv = v2v2 - v1v1
The triangle AOB and PQS are similar. So
= ΔvABΔvAB = vrvr
AB = arc
AB = vΔΔ t
= ΔvvΔtΔvvΔt = vrvr
= ΔvΔtΔvΔt = v2rv2r
= a = v2rv2r
Substitute this value in (1) we get the centripetal force
therefore......
F = mv2rv2r = mrω2
thanks.......!!!!//???
F = ma........(1)
From the figure, we can write the expression
= PQ→PQ→ + QS→QS→ = PS→PS→
= -v1v1 + v2v2
= ΔvΔv
= ΔvΔv = v2v2 - v1v1
The triangle AOB and PQS are similar. So
= ΔvABΔvAB = vrvr
AB = arc
AB = vΔΔ t
= ΔvvΔtΔvvΔt = vrvr
= ΔvΔtΔvΔt = v2rv2r
= a = v2rv2r
Substitute this value in (1) we get the centripetal force
therefore......
F = mv2rv2r = mrω2
thanks.......!!!!//???
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