Question

Centripetal acceleration of electron revolving in a circular orbit of radius 0.5Angstrom is 4×10^11m/s^2 then find its linear speed

Answer 1

$\alpha = v^{2} r \\ 4 \times 10^{11 } = 0.5 \times 10 ^{ - 10} \times v {}^{2} \\ v {}^{2} = \sqrt{8 \times 10 {}^{21 \\ 4 \times 10 { }^{10 \times \sqrt{5} }$