Cerium exhibits +4 oxidation state: give reason
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Answer lies in the electronic configuration of Cerium. Any atom exhibit oxidation state in which it is found to be stable. It is second element of Lanthanide series having atomic number 58. General electronic configuration is
[Xe] 4f1 5d1 6s2.
Lanthanide are very less electronegative. Their electronegative value is nearly equal to s-block elements. So they can lose electrons to form cation. When Cerium loses 4 e-, it will acquire fully field electronic configuration of Xenon (2,8,18,18,8). As fully filed or half filed electronic configuration possesses extra stability.
That is why Cerium exhibits +4 oxidation state.
[Xe] 4f1 5d1 6s2.
Lanthanide are very less electronegative. Their electronegative value is nearly equal to s-block elements. So they can lose electrons to form cation. When Cerium loses 4 e-, it will acquire fully field electronic configuration of Xenon (2,8,18,18,8). As fully filed or half filed electronic configuration possesses extra stability.
That is why Cerium exhibits +4 oxidation state.
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