certain amount of a gas occupies a volume of 0.4 litre at 17 degree celsius.To what temperature should it be heated so that its volume gets (a)doubled (b)reduced to half?
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(a) v1/t1=v2/t2 by charles law
0.4/273+17 Kelvin=0.8/t2
t2=300*2
t2=600 Kelvin
t2=600-273
t2=327 degree celcius
(b)0.4/300=0.2/t2
t2=300/2
t2=150 Kelvin
t2=150-273
t2=-123 degree celcius
0.4/273+17 Kelvin=0.8/t2
t2=300*2
t2=600 Kelvin
t2=600-273
t2=327 degree celcius
(b)0.4/300=0.2/t2
t2=300/2
t2=150 Kelvin
t2=150-273
t2=-123 degree celcius
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