Question

certain amount of energy is measured as 400 units.if the fundamental units of length,mass,time each are doubled the magnitude of same energy in the new system will
be​

Answer 1

Answer:

New Energy = 800 units

Explanation:

Dimensional Formula of Energy : [ ML²T⁻² ]

This is given to be 400 units.

Now according to the new case, the fundamental units of M, L and T are doubled. We are required to find the Energy in new System.

Interpreting it as an equation we get,

⇒ E' = [ 2M. ( 2L )² . ( 2T )⁻² ]

⇒ E' = [ 2M . 4L² . T⁻²/4 ]

⇒ E' = [ 2 M.L².T⁻² ]

⇒ E' = 2 [ E ]

Hence the new energy E' = 2 × 400 units = 800 units.

Answer 2

Answer:

Explanation:

Given :-

Measured amount of Energy = 400 units

The fundamental units of length, mass, time each are doubled the magnitude of the same energy.

To Find :-

New system of Energy

Formula to be used :-

Dimensional Formula of Energy : [ ML²T⁻² ]

Solution :-

Putting all the values, we get

⇒ E' = [ 2M × ( 2L )² × ( 2T )⁻² ]

⇒ E' = [ 2M × 4L² × T⁻²/4 ]

⇒ E' = [ 2 M × L² × T⁻² ]

⇒ E' = 2 [ E ]

Given Energy = 400 units

= 2 × 400

= 800 units.

Hence, the new system will  be​ 800 units.