Physics, asked by veena1561983, 11 months ago

certain amount of energy is measured as 400 units.if the fundamental units of length,mass,time each are doubled the magnitude of same energy in the new system will
be​

Answers

Answered by Steph0303
33

Answer:

New Energy = 800 units

Explanation:

Dimensional Formula of Energy : [ ML²T⁻² ]

This is given to be 400 units.

Now according to the new case, the fundamental units of M, L and T are doubled. We are required to find the Energy in new System.

Interpreting it as an equation we get,

⇒ E' = [ 2M. ( 2L )² . ( 2T )⁻² ]

⇒ E' = [ 2M . 4L² . T⁻²/4 ]

⇒ E' = [ 2 M.L².T⁻² ]

⇒ E' = 2 [ E ]

Hence the new energy E' = 2 × 400 units = 800 units.

Answered by VishalSharma01
87

Answer:

Explanation:

Given :-

Measured amount of Energy = 400 units

The fundamental units of length, mass, time each are doubled the magnitude of the same energy.

To Find :-

New system of Energy

Formula to be used :-

Dimensional Formula of Energy : [ ML²T⁻² ]

Solution :-

Putting all the values, we get

⇒ E' = [ 2M × ( 2L )² × ( 2T )⁻² ]

⇒ E' = [ 2M × 4L² × T⁻²/4 ]

⇒ E' = [ 2 M × L² × T⁻² ]

⇒ E' = 2 [ E ]

Given Energy = 400 units

= 2 × 400

= 800 units.

Hence, the new system will  be​ 800 units.

Similar questions