Certain amount of heat is given to 100 g of copper to increase its temperature by 21 C if the same amount of heat is given to 50 g water then the rise in its temperature is
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Answer:
=4∘C
Explanation:
The amount of heat supplied is given by the
relation Q=mcΔT
Here , m = 100g = 0. 1 kg,c = 400J/ kg -K
ΔT=21 K for copper
Thus,Q = 0.1×400×21 = 840J
Hence , 840=0.05×4200×ΔT
⇒ΔT=4∘C
Answered by
1
Explanation:
The amount of heat supplied is given by the
relation Q = mc∆T
Here , m = 100g = 0. 1 kg,c = 400J/ kg -K
∆T = 21k for copper
thus,. Q =0.1 X 400 X 21 = 840J
Hence , 840 = 0.05 X 4200 X ∆T
∆T = 4°c
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