Question

Certain force acting a 20kg mass changes its velocity from 5ms' tp 2 ms'. Calculate the work done
by the force.
(3)​

Answer 1

Answer:

300 J

Explanation:

Given :

Mass = 20 kg

Initial velocity u = 5 m / sec

Final velocity = 2 m / sec

We have :

W = F s

Also :

F = ma

F = m ( v - u ) / t  [ v = u + a t ]

W = m ( v - u ) s / t

W = m ( v - u ) u

W = 20 ( 5 - 2 ) 5

W = 100 ( 3 ) J

W = 300 J

Hence work done  by the force is 300 J