Question

certain force acting on 20 kg mass changes its velocity from 5 ms-1 to 6 ms -1 calculate the work done by the force

please put the steps ​

Answer 1

Answer:

The Work done is 110 Joule (J)

Explanation:

Mass = 20kg

u = 5m/s

v = 6 m/s

W = Ke = 1/2 m(v^2 - u^2)

= 1/2 × 20 [(6)^2 - (5)^2 ]

= 10 [36 - 25]

= 10 × 11

= 110 J