Question

Certain force acting on 20kg mass changes its velocity from 5ms-1 to 6ms-1. Calculate the work done by the force?
with steps​

Answer 1

Answer:

Work is said to be done when a force applied to an object moves that object. Work done is generally referred to in relation to the force applied while energy is used in reference to other factors such as heat.

Kinetic energy is given by the expression,

(K. E)v = 1/2 mv2

Where,

K. E = Kinetic energy of the object

v = velocity of the object

Kinetic energy when the object was moving with a velocity of 5 m/s

(K. E)5 = 1/2 × 20 × (5)2

(K. E)5 = 250 J

Kinetic energy when the object was moving with a velocity 2 m/s

(K. E)2 = 1 /2 × 20 × (2)2

(K. E)2 = 40 J

Work done = Change in kinetic energy

= 40 J – 250 J

= – 210 J

Therefore, work done = -210 J

Answer 2

Explanation:

Given :          Initial velocity     u=5  m/s

                      Final velocity     v=2  m/s

The work done is equal to the change in the kinetic energy of an object.

W=21m(v2−u2)

W=21×20×(22−52)

⟹W=−210 J