Certain force acting on a 20 kg mass changes its velocity from
5 ms to 2 ms'. Calculate the work done by the force.
A mass of 10 ke is at a noint A on a table It is moved to a point
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Answer:
Work done by the force
= Magnitude of change in K.E.
= (0.5)×20×(5^2) - (0.5)×20×(2^2) J
= 10(25 - 4) J
= 210 J(Answer)
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