Physics, asked by jaydeepprajapati874, 2 months ago

Certain force acting on a 20 kg mass changes its velocity from
5 m s-1 to 2 m s-1 Calculate the work done by the force.

Answers

Answered by NitishKdhiran
1

Answer:

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Explanation:

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Answered by suhasini001
1

Explanation:

Given : Initial velocity u=5 m/s

Final velocity v=2 m/s

The work done is equal to the change in the kinetic energy of an object.

W=

2

1

m(v

2

−u

2

)

W=

2

1

×20×(2

2

−5

2

)

⟹W=−210 J

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