certain force acting on a 20 kg mass changes its velocity from 5m/s to 2m/s. calculate the work done by the force? please explain in detail.
Answers
Answered by
1
Heya!!
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Work done = change in kinetic energy
=) W = 1/2 * m( v^2 - u^2)
= 1/2 * 20 (2^2 - 5^2)
= 10 * - 21
= - 210 J
Negative sign indicates tht work is in opposite direction.
Hope it helps uh :)
-----------------------
Work done = change in kinetic energy
=) W = 1/2 * m( v^2 - u^2)
= 1/2 * 20 (2^2 - 5^2)
= 10 * - 21
= - 210 J
Negative sign indicates tht work is in opposite direction.
Hope it helps uh :)
ronita2:
thank you but i really do not understand this
well.. lemme understand uh
if Uh r in 9th then Uh know abt kinetic energy and work
according to work energy theorem - W = change in kE
i am in 7 standard
Oh!
no problem..
please send a picture of this answer sister told me to do.
Answered by
1
it can be found by the formula of kinetic energy 1/2 mv^2
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