Question

Certain force acting on a 20 kg mass changes its velocity from 5 m/s to 2m/s.Calculate the work done by the force

Answer 1

All of the Work done , done is kinetic energy , So,

1/2 M*(dt)square is dKE.

So, Work done is ,

1/2*20*(5-2)(square)=90 joule.

Answer 2

_/\_Hello mate__here is your answer--

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Given:-

Mass of the body = 20 kg

Initial velocity = 5 m/s

Final velocity = 2 m/s

To find:- work done by body

Solution:-

We know that,

work done =Change in kinetic energy

= 1/2mu^2 - 1/2mv^2

= 1/2m(u^2 − v^2)

= 1/2(20)(5^2 − 2^2)

= 10(25 − 4)

= 210 J

I hope, this will help you.☺

Thank you______❤

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