Question

Certain force acting on a 20kg mass changes its displacement from 5ms-1 to 2ms-1 calculate the work done by the force

Answer 1

Displacement = 3m
V^2=u^2+2as
25-9=2*a*3
a=16/6
=2.6m/s^2
F=ma
20kg*2.6m/s^2=520 N
W=F*s
=520N*3m
=1560J