Physics, asked by aayushsharma5802, 1 year ago

Certain force acting on a 20kg mass changes its velocity from 5ms to 2ms calculate the work done by the force

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Answered by shruti1pathak3
0

Answer:

here's ur answer.......

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Answered by Anonymous
6

hey mate

here is your answer-⬇️⬇️

ᴍᴀss, ᴍ = 20 ᴋɢ

ɪɴɪᴛɪᴀʟ ᴠᴇʟᴏᴄɪᴛʏ, ᴜ = 5 ᴍ/s

ғɪɴᴀʟ ᴠᴇʟᴏᴄɪᴛʏ, ᴠ = 2 ᴍ/s

ᴛɪᴍᴇ, ᴛ = 1s

ғʀᴏᴍ ғɪʀsᴛ ᴇϙᴜᴀᴛɪᴏɴ ᴏғ ᴍᴏᴛɪᴏɴ 

       

       ᴠ = ᴜ + ᴀᴛ

ᴏʀ, ᴀ = (ᴠ - ᴜ)/ᴛ 

 

ᴀ = (2 ᴍs-1 - 5 ᴍs-1)/15

ᴀ = -3 ᴍs-2

ғʀᴏᴍ ᴛʜɪʀᴅ ᴇϙᴜᴀᴛɪᴏɴ ᴏғ ᴍᴏᴛɪᴏɴ,

 

ᴠ² - ᴜ² = 2ᴀs

⇒ (2ᴍs-1)² - (5ᴍs-1)² = 2 x (-3ᴍs-²)

x s

⇒  -21 ᴍ²s-² = -6 ᴍs-² x s

⇒ s = 7/2 ᴍ

ᴡᴏʀᴋ ᴅᴏɴᴇ = ғ x s

ғᴏʀᴄᴇ = ᴍ x ᴀ

ᴛʜᴇʀᴇғᴏʀᴇ,

 

ᴡ = ᴍ x ᴀ x s

    = 20 ᴋɢ x (-3ᴍs-²) x 7/2 ᴍ

   = -210 ᴊᴏᴜʟᴇs

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