Physics, asked by bandayiram019, 14 hours ago

certain force acting on a 20kg mass changes its velocity from 5m/s to 2m/s. calculate the work done by the force?​

Answers

Answered by sakshithakran71
1

Answer:

Answer:

Work is said to be done when a force applied to an object moves that object. Work done is generally referred to in relation to the force applied while energy is used in reference to other factors such as heat.

Kinetic energy is given by the expression,

(K. E)v = 1/2 mv2

Where,

K. E = Kinetic energy of the object

v = velocity of the object

Kinetic energy when the object was moving with a velocity of 5 m/s

(K. E)5 = 1/2 × 20 × (5)2

(K. E)5 = 250 J

Kinetic energy when the object was moving with a velocity 2 m/s

(K. E)2 = 1 /2 × 20 × (2)2

(K. E)2 = 40 J

Work done = Change in kinetic energy

= 40 J – 250 J

= – 210 J

Therefore, work done = -210 J

Answered by cassandrakateespirit
0

Answer:

Work is said to be done when a force applied to an object moves that object. Work done is generally referred to in relation to the force applied while energy is used in reference to other factors such as heat.

Kinetic energy is given by the expression,

(K. E)v = 1/2 mv2

Where,

K. E = Kinetic energy of the object

v = velocity of the object

Kinetic energy when the object was moving with a velocity of 5 m/s

(K. E)5 = 1/2 × 20 × (5)2

(K. E)5 = 250 J

Kinetic energy when the object was moving with a velocity 2 m/s

(K. E)2 = 1 /2 × 20 × (2)2

(K. E)2 = 40 J

Work done = Change in kinetic energy

= 40 J – 250 J

= – 210 J

Therefore, work done = -210 J

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