Physics, asked by aastik53, 1 year ago

Certain force actiong on a 40kg mass changes velocity from 30 m/s to 50 m/s the work done by force is. Ans- 3200J

Answers

Answered by Anonymous
63
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HERE'S THE ANSWER...

_______________________________

⏺️ Mass ( m ) = 40 Kg

⏺️ Final Velocity ( v ) = 50 m/s

⏺️ Initial Velocity Velocity ( u ) = 30 m/s

♠️ According to work energy theorem

⏺️ Work done is equal to change in kinetic energy , i.e

✔️ W = K ( final ) - K ( initial )

⏺️ K( final ) = 1 / 2 m ( v )^2

=> k( final ) = 1 / 2 × 40 ( 50 )^2

=> K( final ) = 20 × 2500

=> k(final ) = 50,000 J

⏺️ Now , K( initial ) = 1 / 2 m ( u )^2

=> K( initial ) = 1 / 2 × 40 × ( 30 )^2

=> K( initial ) = 20 × 900

=> K(initial ) = 18,000 J

♠️ Now by the above statement

=> Work done = k( final ) - k( initial )

=> W = 50,000 - 18,000

=> \boxed{Work\: done \:=\:32,000 \: Joules}

Or Work done = 32 KJ

HOPE HELPED

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Answered by Anonymous
47
W = kf + Ki

W = 1/2 m × v^2 - 1/2 mu^2

W= 1/2 40 × (50)^2 - 1/2 40×(30)^2

W=50000 - 18000

W=32000 J
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