Certain force actiong on a 40kg mass changes velocity from 30 m/s to 50 m/s the work done by force is. Ans- 3200J
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Answered by
63
HERE'S THE ANSWER...
_______________________________
⏺️ Mass ( m ) = 40 Kg
⏺️ Final Velocity ( v ) = 50 m/s
⏺️ Initial Velocity Velocity ( u ) = 30 m/s
♠️ According to work energy theorem
⏺️ Work done is equal to change in kinetic energy , i.e
✔️ W = K ( final ) - K ( initial )
⏺️ K( final ) = 1 / 2 m ( v )^2
=> k( final ) = 1 / 2 × 40 ( 50 )^2
=> K( final ) = 20 × 2500
=> k(final ) = 50,000 J
⏺️ Now , K( initial ) = 1 / 2 m ( u )^2
=> K( initial ) = 1 / 2 × 40 × ( 30 )^2
=> K( initial ) = 20 × 900
=> K(initial ) = 18,000 J
♠️ Now by the above statement
=> Work done = k( final ) - k( initial )
=> W = 50,000 - 18,000
=>
Or Work done = 32 KJ
HOPE HELPED
:)
Anonymous:
thank you miss ☺️
Answered by
47
W = kf + Ki
W = 1/2 m × v^2 - 1/2 mu^2
W= 1/2 40 × (50)^2 - 1/2 40×(30)^2
W=50000 - 18000
W=32000 J
W = 1/2 m × v^2 - 1/2 mu^2
W= 1/2 40 × (50)^2 - 1/2 40×(30)^2
W=50000 - 18000
W=32000 J
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