Certain mass of a gas occupies 20litre volume at 300k and 2atm pressure.calculate molecules of the gas present in it
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Explanation:we know that
p1v1/t1 p2v2/t2
where
p1=pressure given which is 1.2
p2 =1 (stp)
v1 =volume given
v1=volume at stp
t1=temperature given
t2=temperature at stp
we need to change the volume according to stp
putting value
1.2×20/300=1×v2/273
v2=21.84 l
now,no. of moles =21.84/22.4=0.975
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