certain quantity of heat cools from 70°c to 60° c in the first 5 mint and 54°c in the next,5 min.the what will. be the temperature of the surrounding
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Answer:
45°C
Explanation:
60-70÷5= -k (65-T)
54-60÷4= k (57-T)
-10÷6= 65-T ÷ 57-T
285-5T= 195-3T
90=2T
T=45°C
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