Question

certain region has an electric field E = (2 i - 3 j) N/C and a uniform magnetic field B = (5 i + 3 j+ 4 k) T. The force experienced by a charge 1C moving with velocity (i + 2 j) m/s is: (4 marks)​

Answer 1

Answer:

√198

Explanation:

F=qE+q(v×B)

this is loranze force

Answer 2

Answer:

The force experienced by a charge 1C is 10i - 7j -7k N.

Explanation:

Given:

V = 1i + 2j m/s

E = 2i - 3j N/C

q = 1C

B = 5i + 3j + 4k T

Here,

The force is denoted by F.

The electric field is denoted by E.

The magnetic field is denoted by B.

The charge is denoted by q.

The speed is denoted by V.

Now,

By the equation,

F = qE + q(V × B)

F = 1 × (2i - 3j) + 1 × [(1i + 2j) × (5i + 3j +4k)]

F = 10i - 7j -7k N

So, the force experienced by a charge 1C is 10i - 7j -7k N.