Question

cest quoi une modèle de Shannon?

Answer 1

Answer:

Radius of the roller (r) = 84/ 2 cm = 42 cm Length of the roller (h) = 120 cm Curved surface area of the roller = 2πrh = 2 × 22/ 7 × 42 × 120 cm2 = 44 × 720 cm2 = 31680 cm2 ∴ area covered by the roller in 1 revolution = 31680 cm2 ∴ area covered by the roller in 500 revolutions = 31680 × 500 cm2 = 15840000 cm Hence, area of the playground = 15840000/ 100× 100 m2 = 1584 m2

Answer 2

Answer:

Radius of the roller (r) = 84/ 2 cm = 42 cm Length of the roller (h) = 120 cm Curved surface area of the roller = 2πrh = 2 × 22/ 7 × 42 × 120 cm2 = 44 × 720 cm2 = 31680 cm2 ∴ area covered by the roller in 1 revolution = 31680 cm2 ∴ area covered by the roller in 500 revolutions = 31680 × 500 cm2 = 15840000 cm Hence, area of the playground = 15840000/ 100× 100 m2 = 1584 m2

Answer 3

Answer:

Radius of the roller (r) = 84/ 2 cm = 42 cm Length of the roller (h) = 120 cm Curved surface area of the roller = 2πrh = 2 × 22/ 7 × 42 × 120 cm2 = 44 × 720 cm2 = 31680 cm2 ∴ area covered by the roller in 1 revolution = 31680 cm2 ∴ area covered by the roller in 500 revolutions = 31680 × 500 cm2 = 15840000 cm Hence, area of the playground = 15840000/ 100× 100 m2 = 1584 m2