Question

Cg H8=
+ O2
CO2 +H20 how do balance it by abc method

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Answer 1

Correct Question $\longrightarrow$

Balance the following equation by algebraic method.

$C_6H_8 + O_2 = CO_2 + H_2O$

Solution $\longrightarrow$

Equation

$aC_6H_8 + bO_2 = cCO_2 + dH_2O$

For

C atom $\longrightarrow$6a = c

H atom $\longrightarrow$8a = 2d

O atom$\longrightarrow$2b = 2c + d

Let the value of a = 1

c = 6a = 6

8a = 2d$\longrightarrow$ 8 × 1 = 2 × d$\longrightarrow$d = 4

2b = 2c + d $\longrightarrow$2b = 2 × 6 + 4 $\longrightarrow$

b = 16/2 = 8

Balanced equation $\longrightarrow$

$C_6H_8 + 8O_2 = 6CO_2 + 4H_2O$

Verification$\longrightarrow$

C atom$\longrightarrow$ 6 = 6

H atom$\longrightarrow$8 = 8

O atom$\longrightarrow$16 = 12 + 4 16 = 16

Additional information$\implies$

$\implies$Chemical equation - It is representation of chemical reaction in form of word or formula in which left side is reactant and right side is product.

$\implies$Balanced chemical equation - The equation in which atoms of reactant and product are equal.

$\implies$Equation is balanced to fulfil the law of conservation of mass.

Thanks

Answer 2

Answer:

AnswersChemistryGCSEArticle

Balance the following equation: C3H8 + O2 ----> CO2 + H2O. (There will be no need for state symbols.)

First of all, to balance these equations, list the number of each atom, for both sides of the equation. In this example, it would be:

Carbon: 3 Carbon: 1

Hydrogen: 8 Hydrogen: 2

Oxygen: 2 Oxygen: 3

The first step would be to balance out the carbons on the products side by multiplying CO2 by 3. The new equation will be

C3H8 + 02 ----> 3CO2 + H20

Now, the carbons are balanced, we will look at the hydrogens. We can multiply the number of waters on the product side by 4, to make 4 H20 molecules. This gives both sides of the equation 8 hydrogens. Next we can check our oxygens. There will be 10 oxygens on the products side and 2 on the reactants so to balance these out, we multiply the 02 on the reactants side by 5.

The final equation will be C3H8 + 502 ----> 3CO2 + 4H20.