ch-1 class 11 chemistry send me immediately plzz
calculate the number of oxygen atoms in the following compound :
(a)10 moles of CaCO3
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Mass of CaCO
3
= 40+12+48 = 100g
Moles of CaCO
3
=
100
300
= 3
Number of molecules of CaCO
3
= 3×6.02×10
23
1 molecule of CaCO
3
contain 3 atoms of oxygen
3×6.02×10
23
molecule will contain 3×3×6.023×10
23
=54.027×10
23
atoms
3
= 40+12+48 = 100g
Moles of CaCO
3
=
100
300
= 3
Number of molecules of CaCO
3
= 3×6.02×10
23
1 molecule of CaCO
3
contain 3 atoms of oxygen
3×6.02×10
23
molecule will contain 3×3×6.023×10
23
=54.027×10
23
atoms
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