Math, asked by banusreya37, 10 months ago

ch-10 abcd is a cyclic quadrilateral . if AC bisects both the angles A and C , then prove that angle ABC =90 °​

Answers

Answered by kannankeerthi52
10

Step-by-step explanation:

In the triangles ABC & ADC

∠BAC=∠DAC

∠DCA=∠BCA

AC=CA

ΔABC & ΔADC are congruent

∠CDA=∠ABC

∠CDA+∠ABC=180° (opposite angle of a cyclic quadrilateral are supplementary)

2ABC=180°

∠ABC=180/2

∠ABC=90°

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