ch-10 abcd is a cyclic quadrilateral . if AC bisects both the angles A and C , then prove that angle ABC =90 °
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Step-by-step explanation:
In the triangles ABC & ADC
∠BAC=∠DAC
∠DCA=∠BCA
AC=CA
ΔABC & ΔADC are congruent
∠CDA=∠ABC
∠CDA+∠ABC=180° (opposite angle of a cyclic quadrilateral are supplementary)
2ABC=180°
∠ABC=180/2
∠ABC=90°
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