Question

Ch 13 Algebraic Identities (4p+3) (4p+7) find the product​

Answer 1

Answer:

16p^2 + 40p + 21 is answer of this question

Answer 2

Answer:

16p² + 40p + 21

Step-by-step explanation:

(4p + 3)(4p + 7)

= 16p² + 12p + 28p + 21

= 16p² + 40p + 21

Therefore, Product of (4p + 3) and (4p + 7) is 16p² + 40p + 21.

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