ch 4 claas 10 ex 4.2 no 6
Answers
Class 10 chapter 4 exercise 4.2 no. 6.
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6) A cottage industry produce a certain number of pottery articles in a day. It was observed on a particular day that the cost of production of each Article (in rupees) was 3 more than twice the number of articles produced on that day was Rs.90, find the number of articles produced and the cost of each Article.
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Let the number of articles produced be x.
therefore, the cost of production of each Article = Rs(2x + 3)
Given that,
total cost production of is Rs.90
=> X(2x + 3) = 90
=> 2x² + 3x - 90 = 0
=> 2x² + 15x - 12x - 90 = 0
=> x(2x + 15) -6(2x + 15) = 0
=> (2x + 15) (x-6) = 0
[As the number of articles produced can only be a positive integer therefore, x can only be 6]
Hence number of articles produced = 6
cost of each Article = 2×6+3 = Rs.15
Answer:
Class 10 chapter 4 exercise 4.2 no. 6.
♡ǫᴜᴇsᴛɪᴏɴ ♡
6) A cottage industry produce a certain number of pottery articles in a day. It was observed on a particular day that the cost of production of each Article (in rupees) was 3 more than twice the number of articles produced on that day was Rs.90, find the number of articles produced and the cost of each Article.
♡ᴀɴsᴡᴇʀ ♡
Let the number of articles produced be x.
therefore, the cost of production of each Article = Rs(2x + 3)
Given that,
total cost production of is Rs.90
=> X(2x + 3) = 90
=> 2x² + 3x - 90 = 0
=> 2x² + 15x - 12x - 90 = 0
=> x(2x + 15) -6(2x + 15) = 0
=> (2x + 15) (x-6) = 0
[As the number of articles produced can only be a positive integer therefore, x can only be 6]
Hence number of articles produced = 6
cost of each Article = 2×6+3 = Rs.15