Ch.6 Circle std =9th
The radius of the circle is 6 cm. The perpendicular
distance from the centre of the circle to the chord,
which is 8 cm in length, is .... ?
(A) 2.5 cm
(B) 13 cm
(C) 5 cm
(D) 17 cm
please explain step by step
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Answer:
we know that perpendicular drawn from the center to the chord divides the chord into two equal parts
so, AM=MB
=AB/2
=8/2
=4cm
using pythogoras therom in the ∆AMO
OM^2= AO^2-AM^2
= 6^2-4^2
=√20
=2√5
=5
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