Question

Ch-6,Factorisation of algebraic expression

Answer 1

Answer:

(q+1) (pq-1)

Step-by-step explanation:

>>> pq²+q(p-1)-1 ... opening bracket

==> pq²+pq -q-1 ... talking pq common

==> pq(q+1) -q-1 ... talking -1 common

==> pq(q+1) -1(q+1) ... talking q+1 common

==> (q+1) (pq-1)

Answer 2

• We have to evaluate the above expression by using the given data.

             Given data:- $\mathrm{pq}^{2}+\mathrm{q}(\mathrm{p}-1)-1.$

             To find:- Value of the expression.

             Solution:-

• We know that factorization means reducing any algebraic or quadratic equation.

• Steps to solve quadratic equations,

• Step 1: Rearrange the given quadratic so that is it equal to zero.

• Step 2: Factorise the quadratic.

• Step 3: Form two linear equations.

• Step 4: Solve the equations to find the roots of the equation.

        Therefore,

       firstly let's simplify

      $\mathrm{pq}^{2}+\mathrm{q}(\mathrm{p}-1)-1\\\\=\mathrm{pq}^{2}+\mathrm{pq}-\mathrm{q}-1\\\\=(\mathrm{q}+1)-1(\mathrm{q}+1)\\\\=(\mathrm{q}+1)(\mathrm{pq}-1).$

     Hence we will get $\mathrm{pq}^{2}+\mathrm{q}(\mathrm{p}-1)-1=(q+1)(p q-1).$