Chemistry, asked by veeananushka2002, 3 months ago

CH-C(CH3) =CH-CH3+B2H6/THF/H202/OH-=

Answers

Answered by Anonymous

1

CH3-CH=CH2+B2H6+ 3H2O2/OH->CH3CH2CH2OH

Thus, CH3 CH=CH2 when treated with B2H6 in presence of H2O2 will give the final product as : CH3CH2CH2OH .

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