Question

CH. CH=CH
on oxymercuration demercuration produces
CH-CH=CH
OH
CH, CH, -CH=-- OH
(2)
CH, CHOH – CHOH
(3)
11 H
CC-CH
Mark for Review & Next
Clear Response​

Answer 1

Answer:

—— (1) : (2)

A:B = 2 : 3

B:C = 4 : 5

C:D = 6 : 7

A is the product of all terms appearing under column (1).

A = 2 x 4 x 6 = 48

B is the product of all terms under column (1) beginning from second row and term under column (2) for all previous rows.

B = 4 x 6 x 3 = 72

C is the product of all terms under column (1) beginning from third row and terms under column (2) for all previous rows.

C = 6 x 3 x 5 = 90

D is the product of all terms appearing under column (2).

D = 3 x 5 x 7 = 105

=> A:B:C:D = 48:72:90:105

You can find ratio between any two or three variables from above.

A:D = 48:105 = 16:35

Note : This logic can be extended to any number of rows

If A:B, B:C, C:D, D:E, E:F, F:G, G:H, H:I is given, we can find A:B:C:D:E:F:G:H:I using above method.