Question

Ch exponent and Powers class 8 Simplify it.​

Answer 1

$\tt{ {\dfrac{ {(16)}^{-1} × 125}{ {(2)}^{-5} }}}$

$\tt{\implies {\dfrac{ {(2^4)}^{-1} × 125}{ {(2)}^{-5}}}}$

$\tt{\implies {\dfrac{ {(2)}^{-4} × 125}{ {(2)}^{-5}}}}$

$\tt{\implies {(2)}^{(-4) - (-5)} × 125}$

$\tt{\implies {(2)}^{1} × 125}$

$\tt{\implies 250}$