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In a quadrilateral ABCD, A=66, B=(C+16), C=6(x+4) and D= (A-16), calculate B and D.
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Answer:
D=(A-16)
as A= 66 then A-16= 66-16= 50
In the same way:
c=6(x+4)= 6x+24= substitute 6x+24 in place of c, then B= 6x+24+16=6x+40
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