Ch:Perimeter and Area
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by pythagorous theorm
H^2=B^2+P^2
(17)^2=(8)^2+P^2
289=64+P^2
289-64=P^2
in root 225=P
15=p
area of triangle =1/2×b×h
1/2×8×15
120/2=60 cm ^2
H^2=B^2+P^2
(17)^2=(8)^2+P^2
289=64+P^2
289-64=P^2
in root 225=P
15=p
area of triangle =1/2×b×h
1/2×8×15
120/2=60 cm ^2
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