Question

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Tina ran around a rectangular garden of length 12 metres and breadth
8 metres. Meena ran around a square field of side 11 metres. Who covered more distance and by how much?​

Answer 1

ANSWER :

• When Tina ran around a rectangular garden of length 12 metres and breadth 8 metres and Meena ran around a square field of side 11 metres, Meena covers more distance by 4 metres than Tina.

$\underline{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }$

SOLUTION :

❒ Given :-

• Tina ran around a rectangular garden of length 12 metres and breadth 8 metres.

• Meena ran around a square field of side 11 metres.

❒ To Find :-

• Who covered more distance.

• How much more distance covered.

❒ Required Formulas :-

• Perimeter of rectangle = 2 (Length + Breadth)

• Perimeter of square = 4 × Side

❖ Calculation of distance covered by Tina :-

➦ Tina ran around the rectangular field having,

• Length = 12 m

• Breadth = 8 m

∴ Distance covered by Tina = Perimeter of the rectangular field

= 2 (Length + Breadth)

= [ 2 (12 + 8) ] m

= (2 × 20) m

= 40 m

• Hence, Tina convered the distance of 40 m.

❖ Calculation of distance covered by Meena :-

➦ Meena ran around a square field having,

• Length of each side = 11 m

∴ Distance covered by Meena = Perimeter of the square field

= 4 × Side

= (4 × 11) m

= 44 m

• Hence, Meena convered the distance of 44 m.

★ As distance covered by Meena is greater than distance covered by Tina; therefore, Meena covered more distance.

$\underline{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:\: \: \: \: \: \: \: \: \: \: \: \: \:}$

❖ Calculation of difference of distance covered by Tina

and Meena :-

We have,

• Distance covered by Tina = 40 m

• Distance covered by Meena = 44 m

∴ Difference = Distance covered by Meena - Distance covered by Tina

= 44 m - 40 m

= 4 m

• Hence, the difference is 4 m.

★ As the difference of distance covered by Tina and Meena is 4 m; therefore, Meena covered more distance by 4 m than Tina.

Answer 2

$\fbox \purple{❒ Given}$

Tina ran around a rectangular garden of length 12 metres and breadth 8 metres.

Meena ran around a square field of side 11 metres.

$\fbox \pink{❒ Given}$

• Who covered more distance.
• How much more distance covered.

$\fbox \red{Perimeter of rectangle = 2 (Length + Breadth)}$

$\fbox \orange{Perimeter of square = 4 × Side}$

$\fbox \green{Calculation of distance covered by Tina :-}$

⇛ Tina ran around the rectangular field having,

• Length = 12 m
• Breadth = 8 m

Distance covered by Tina = Perimeter of the rectangular field

= 2 (Length + Breadth)

= [ 2 (12 + 8) ] m

= (2 × 20) m

= 40 m

$\fbox \blue{Tina convered the distance of 40 m.}$

$\fbox \green{Calculation of distance covered by Meena}$

⇛Meena ran around a square field having,

Length of each side = 11 m

Distance covered by Meena = Perimeter of the square field

= 4 × Side

= (4 × 11) m

= 44 m

$\fbox \blue{Meena convered the distance of 44 m.}$

As distance covered by Meena is greater than distance covered by Tina; therefore, Meena covered more distance.

$\fbox \green{Calculation of difference of distance covered by Tina and meera}$

We have,

Distance covered by Tina = 40 m

Distance covered by Meena = 44 m

∴ Difference = Distance covered by Meena - Distance covered by Tina

= 44 m - 40 m

= 4 m

Hence, the difference is 4 m.

As the difference of distance covered by Tina and Meena is 4 m; therefore, Meena covered more distance by 4 m than Tina.

$\fbox \pink{ハンはジャクソンが大好き}$